Question

(k +4b) (5a -4b) = 25a square - 16b square then k =​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Given,

$(k +4b) (5a -4b) = 25a^2 - 16b^2$

To Find,

Value of k =?

Solution,

$(k +4b) (5a -4b) = 25a^2 - 16b^2$

Taking the right-hand side first, we get

R.H.S = $25a^2 - 16b^2$

We can also write is as

R.H.S = $(5a)^2 - (4b)^2$ [25 and 16 are squares of 5 and 4]

R.H.S = $(5a)^2 - (4b)^2$

Using the formula, $a^2 - b^2 = (a - b) (a + b)$ we can write it as,

R.H.S. = $(5a + 4b)(5a - 4b)$

Now putting L.H.S. =  R.H.S.

$(k +4b) (5a -4b) =(5a+4b)(5a - 4b)$

(5a -4b) is common so cancel out them

$(k + 4b) = (5a + 4b)$

$k + 4b -4b = 5a$

k = 5a

Hence, the value of k is 5a