k+h2o -> koh+h2 how to balance it
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1
Explanation:
2K + 2H(2)O —->2KOH + H(2) There is no way to get a water molecule in the product and balance the equation, I changed it to (H2) in gaseous form.
chinmayees829:
i need step by step answer
2 HI + 2 e- → 2 H0(reduction)
2 K0 - 2 e- → 2 KI(oxidation)
H2O is an oxidizing agent, K is a reducing agent.
Answered by
0
Answer:
2k+2h2o->2koh+h2 (balanced)
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