Math, asked by yuseraansari1998, 16 days ago

K) In AABC, AB = 12 cm, BC= 9 cm and AD = 6 cm (see fig). Find the: 1) area of AABC 2) altitude CE​

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Answers

Answered by niharika23870
0

Step-by-step explanation:

In triangle ABC, AD = 6 cm and BC = 9 cm

Area of triangle ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 cm × 6 cm

= 27 cm2

Now, Area of triangle ABC = 1/2 × AB × CE

27 cm2 = 1/2 × 7.5 cm × CE

CE = (2 × 27 cm2) / 7.5 cm

CE = 54 cm2 / 7.5 cm

CE = 7.2 cm

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