k is twice as old as r. three years ago, k was three times as old as r. the present age of k (in years) is
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let the present age of r be x
then, present age of k =2x
3 years ago ,
age of r= x-3
age of k= 2x - 3
so,
3(x-3) = 2x - 3
3x - 9 = 2x - 3
3x- 2x = 9 - 3
therefore,
x = 6
hence,
present age of r=6 years
present age of k= 2× 6= 12 years
then, present age of k =2x
3 years ago ,
age of r= x-3
age of k= 2x - 3
so,
3(x-3) = 2x - 3
3x - 9 = 2x - 3
3x- 2x = 9 - 3
therefore,
x = 6
hence,
present age of r=6 years
present age of k= 2× 6= 12 years
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