Question

(k,k),(2,3),(4,1)are collinear then find k​

Answer 1

Answer:

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Answer 2

Answer:

Mark the coordinates as A, B, C respectively.

If the point are collinear then Area of triangle is 0.

So,

=> 1/2 [ k( 3-1) + 2(1-k) + 4(k-3)] = 0

=> 1/2 [ 2k + (2- 2k) + (4k-12)] = 0

=> 1/2 [ 2k + 2 - 2k + 4k - 12] = 0

=> 1/2 [4k - 10] = 0

=> 2k - 5 = 0

=> k = 5/2