Math, asked by lxmnrnseth, 11 months ago

K के किस मान के लिए निम्न रैखिक समीकरणों के युग्म का कोई हल नही है?
3x+y=1 और (2k-1)x + (k-1)y=2k+1

Answers

Answered by harman1871
10

Answer:

Hey mate ,

here's ur answer

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k = 2

Step-by-step explanation:

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For the linear equation to have no solution it must be in the form of a1/a2 =b1/b2 not equal to c1/c2

(2k-1)x +(k-1)y=2k+1 ----------eq. 1

3x+y=1 -----------eq.2

a1/a2=(2k-1)/3

b1/b2=(k-1)/1

by cross multiplying a1/a2 withb1/b2 , we get ;

2k-1=3 (k-1)

2k-1=3k-3

2k-3k=-3+1

-k=-2

k=2

put value of k in (2k-1) and (k-1)

2 (2) -1 =4 -1 =3 and 2 - 1 =1

3/3=1/1 ______ 1/1 =1/1

a1/a2 =b1/b2

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hope it will be helpful for you

plz mark as brainliest ☺

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