Question

K-p for the equation A(s) = B(g) + C(g) + D(s) is
9 atm2. Then the total pressure at equilibrium will
be
(1) 3 atm
(2) 9 atm
(3) 6 atm
(4) 12 atm​

Answer 1

$\large{\sf A_s→B_g+C_g+D_s }$

At equilibrium 0 = $\alpha$ $\alpha$

Now ,

Equilibrium Constant $\sf{K_P= P_c×P_D}$

9 atm² = $\alpha$ $\alpha$

9 = ${(\alpha)^2}$

$\alpha$ = 3

Hence ,

Equilibrium Pressure of gaseous mixture is= $\alpha$+ $\alpha$

$\implies{\sf 2\alpha}$

$\implies{\sf 2×3 }$

$\implies{\sf 6\:atm }$

$\Large\underline{\underline{\sf Answer:}}$

•°• Total pressure at equilibrium is 6 atm.

Answer 2

$\huge{\boxed{\boxed{\mathfrak{\pink{Answer}}}}}$

(3) 6 atm