Question

K+ [pt(nh3)12] how to calculate the EAN ?
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Answer 1

Answer:

EAN = 88

Explanation:

EAN = Effective Atomic Number

EAN = Z - X + Y

where, Z - atomic no. of metal

           X - no. of electrons lost during ion formation

           Y - no. of electrons gained from ligands.

Here, Z = 78 (atomic number of platinum is 78)

          X = 2 ( 2 ions i.e. $K^+$ and $[Pt(NH_3)_6]^-$ are produced)

          Y = 12 ( 6 NH₃ are there, each giving 2 $e^-$ so, 6 x 2 = 12 )

⇒   EAN  = 78 - 2 + 12

               = 76 + 12

 ∴  EAN  = 88