Math, asked by kailash27, 1 year ago

k quabe + 2 k square + 9k- 132 =0 find
k \: quabe + 2k \: square + 9k - 132 = 0

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Answered by Kanagasabapathy
1
if you feeling better.... mark me as brainliest.......sry ans is (k-4),-3(+r-)√42
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