Question

k=(x^2-1)/x^2+3x+2
Find the value of k for which the equation has no solution? ​

Answer 1

Answer:

k=(x-1)/(x+2)

Step-by-step explanation:

k=(x^2-1)/x^2+3x+2

=[(x) ^2-(1)^2]/[x^2+2x+x+2]

=[(x+1)(x-1)]/[x(x+2)+1(x+2)]

=[(x+1)(x-1)]/[(x+2)(x+1)] (From both sides (x+1) gets cut)

Therefore,

k=(x-1)/(x+2)