k=(x^2-1)/x^2+3x+2
Find the value of k for which the equation has no solution?
Attachments:
Answers
Answered by
1
Answer:
k=(x-1)/(x+2)
Step-by-step explanation:
k=(x^2-1)/x^2+3x+2
=[(x) ^2-(1)^2]/[x^2+2x+x+2]
=[(x+1)(x-1)]/[x(x+2)+1(x+2)]
=[(x+1)(x-1)]/[(x+2)(x+1)] (From both sides (x+1) gets cut)
Therefore,
k=(x-1)/(x+2)
Similar questions