Question

K=?
x=(-2)
2x^2+kx-2=0
​

Answer 1

Answer:

3

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\boxed{ \colorbox{red}{ \huge{Given}}}$

$2 {x}^{2} + kx - 2 = 0$

$2 {( - 2)}^{2} + - 2k - 2 = 0$

$2(4) - 2k - 2 = 0$

$8 - 2k - 2 = 0$

$- 2k = - 8 + 2$

$\not{ -} 2k = \not - 6$

$k = \frac{6}{2}$

$\textit{ \boxed{k = 3}}$