Question

k (x) square -(x)+6=0 if x=-2​

Answer 1

Answer:

$k {x}^{2} - x + 6 = 0 \: \: \: \: < x = - 2 > \\ then \: \\ k \times ( - 2) {}^{2} - ( - 2) + 6 = 0 \\ 4k + 2 + 6 = 0 \\ 4k = - 8 \\ k = \frac{ - 8}{4} = - 2$