Chemistry, asked by niamthao4658, 11 months ago

K₁ and K₂ are equilibrium constant for reactions (i) and (ii)
N_2(g) + O_2 (g) \rightleftharpoons 2NO(g) ...(i)
NO(g) \rightleftharpoons \frac{1}{2} N_2(g) + \frac{1}{2}O_2(g) ...(ii)
Then,
(a) K_1 = \bigg \lgroup \frac{1}{K_2}\bigg \rgroup ^2
(b) K_1 = K_2^2
(c) K_1 = \frac{1}{K_2}
(d) K_1 = (K_2)^0

Answers

Answered by StylishhhhGirl
0

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Answered by Anonymous
0

Hello Friend

The answer of u r question

Option.D

Thank you

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