Chemistry, asked by marvinjose004, 8 months ago

k1
H2(aq) + I2(g) ↔ 2HI(g)
k2
At the given temperature, the forward rate constant k1, for the one step reaction shown above is 4*10^-7 M^-1 s^-1. Given that the equilibrium constant is 1*10^-2, what is the reverse rate constant k-1?

a) 8*10^-5 M^-1 s^-1
b) 4*10^-5 M^-1 s^-1
c) 4*10^-7 M^-1 s^-1
d) 8*10^-9 M^-1 s^-1
e) 4*10^-9 M^-1 s^-1. ​

Answers

Answered by niyaticku24
0

Answer:

option c is correct answer

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