K1, K2, K3 are equilibrium constants for following
reactions
X + 2Y =Z;
K
Z + P 3X;
K
6Y + P 22Z;
K3
Then which is correct relation?
(1) 3K, K2 = K2
(2) Ki K3 =
ki Kg
(3) 3K, K3 = K
(4) KK = K3
Answers
Answered by
0
Answer:
2NO+O
2
⇌2NO
2
K
1
=
[NO]
2
[O
2
]
[NO
2
]
2
... (ii)
4NO+2Cl
2
⇌4NOCl
K
2
=
[NO]
4
[Cl
2
]
2
[NOCl]
4
...(ii)
NO
2
+
2
1
Cl
2
⇌NOCl+
2
1
O
2
K
3
=
[NO
2
][Cl
2
]
1/2
[NOCl][O
2
]
1/2
.... (iii)
divide K
2
by square of K
1
2
[NO]
4
[Cl
2
]
2
[NOCl]
4
×
[NO
2
]
4
[NO]
4
[O
2
]
2
=
[NO
2
]
4
[Cl
2
]
2
[NOCl]
4
[O
2
]
2
K
2
×
K
1
2
1
=K
3
4
⇒
K
1
2
K
2
=K
3
4
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