Question

k²-3k-3=0 find value of k

Answer 1

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$k {}^{2} - 3k - 3 = 0 \\ k {}^{2} - 3k + k - 3 = 0 \\ k(k - 3) + 1(k - 3) = 0 \\ (k + 1)(k - 3) = 0 \\ k = - 1 \: and \: k = 3$
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