Chemistry, asked by moiz3064, 4 months ago

K2 Cr2 O7 find out the oxidation state of Cr2​

Answers

Answered by Anonymous
0

Explanation:

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Answered by ItzVenomKingXx
3

Let the Ox. no. of Cr in  \tt K_2 Cr_2 O_7 be x.

We know that, Ox. no. of K=+1

Ox. no. of O=−2

So, 2(Ox.no.K)+2(Ox.no.Cr)+7(Ox.no.O)=0

2(+1)+2(x)+7(−2)=0

or +2+2x−14=0

or 2x=+14−2=+12

Hence, oxidation number of Cr in \tt K_2 Cr_2 O_7 +6.

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