Question

K2CO3 cannot be prepared by Solvay's process because
(a) KHCO3 is less soluble than NaHCO3
(b) KHCO3 is too soluble to be precipitated by KCI
and NH4HCO3
(c) K2CO3 is too soluble to be precipitated by KCI
(d) K2CO3 is less soluble than Na2CO3.​

Answer 1

The answer is option d, because unlike sodium bicarbonate,potassium bicarbonate is partially soluble in water and does not precipitate out

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Answer 2

Explanation:

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