K2CO3 in 2dm^3 of 2 mole solution, calculate the mass... pls it's urgent
Answers
Answer:
276g of K₂CO₃
Explanation:
Calculate the weight of K₂CO₃ in 2 moles:
K = 39g, C = 12g, O = 16g
1 mole K₂CO₃ = (39 × 2) + 12 + (16 × 3)
= 78 + 12 + 48
= 138g
∴ 2 moles K₂CO₃ = 138 × 2
= 276g
∴ There is 276g of K₂CO₃ in 2dm³ of the solution
(I'm sorry if this is not what you were asking for...I tried my best to work with the information given.)
Hope this helps! :)
- Abby <3
Answer:
Hey mates
Here is your answer
276g of K₂CO₃
Explanation:
Calculate the weight of K₂CO₃ in 2 moles:
K = 39g, C = 12g, O = 16g
1 mole K₂CO₃ = (39 × 2) + 12 + (16 × 3)
= 78 + 12 + 48
= 138g
∴ 2 moles K₂CO₃ = 138 × 2
= 276g
∴ There is 276g of K₂CO₃ in 2dm³ of the solution
(I'm sorry if this is not what you were asking for...I tried my best to work with the information given.)
Hope this helps! :)