Question

K2Cr207 find the oxidation state​

Answer 1

Answer:

So, the total charge of potassium ions is +1⋅2=+2 , while oxygen ions is −2⋅7=−14 . Let x be the oxidation number of two chromiums. So, two chromium atoms have an oxidation number of +12 , and so one chromium atom will have an oxidation number of +122=+6

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Answer 2

Answer:

Potassium dichromate, contains the dichromate ion, in which chromium is in its hexavalent form, i.e. chromium(VI).

We can prove it as follows.

In K2Cr2O7, potassium has a +1 charge, and oxygen has a −2 charge.

So, the total charge of potassium ions is +1⋅2=+2, while oxygen ions is −2⋅7=−14.

Let x be the oxidation number of two chromiums.

So, we got:

2+x−14=0

−12+x=0

x=12

So, two chromium atoms have an oxidation number of +12, and so one chromium atom will have an oxidation number of +122=+6.

Explanation: