Question

K2Cr2O7+H2SO4+SO2= K2SO4+Cr2(SO4)3+H2O

Answer 1

Answer:

K2Cr2O7 + 3 SO2 + H2SO4 → Cr2(SO4)3 + K2SO4 + H2O

Explanation:

This is an oxidation-reduction (redox) reaction:

3 SIV - 6 e- → 3 SVI

(oxidation)

2 CrVI + 6 e- → 2 CrIII

(reduction)

SO2 is a reducing agent, K2Cr2O7 is an oxidizing agent.