K₂Cr₂O7 + H₂SO4 + SO₂→ K2SO4 + Cr₂(SO4)3 + H₂O balance this equastion by partial reaction equastion
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Answer:
SO
2
+2H
2
O⟶(SO
4
)
2−
+4H
+
+2e
−
……(1)
(Cr
2
O
7
)
2−
+14H
+
+6e
−
⟶2G
3+
+7H
2
O…(2)
Multiplying (1) by 3 and adding (2),
3SO
2
+(Cr
2
O
7
)
2−
+2H
+
⟶3(SO
4
)
2−
+2Cr
3+
+H
2
O
Completing the reaction,
K
2
Cr
2
O
7
+H
2
SO
4
+3SO
2
⟶K
2
SO
4
+Cr
2
(SO
4
)
3
+H
2
O
Here, X=1,Y=3,Z=1
Explanation:
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