Chemistry, asked by rteja5196, 24 days ago

K2cr2O7+HCI =KCI+CRCL3+H2O+CI2

Answers

Answered by sreejahailants

0

Explanation:

HCl is a reducing agent, K 2Cr 2O 7 is an oxidizing agent. , [Note: Often used in an aqueous solution.]

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Search by products (CrCl 3, Cl 2, KCl, H 2O)

1 2

1 HCl + K2Cr2O7 → H2O + Cl2 + KCl + CrCl3

2 HCl + K2CrO4 → H2O + Cl2 + KCl + CrCl3

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