Chemistry, asked by vishakha3031, 10 months ago

K2Cr2O7+HCl-------->>KCl+CrCl3+H2O+Cl2
Write the equation in ionic form ​

Answers

Answered by saumyashukla1420
2

K2Cr2O7 + 14 HCl → 2 CrCl3 + 3 Cl2 + 2 KCl + 7 H2O

This is an oxidation-reduction (redox) reaction:

6 Cl-I - 6 e- → 6 Cl0(oxidation)

2 CrVI + 6 e- → 2 CrIII(reduction)

HCl is a reducing agent, K2Cr2O7 is an oxidizing agent.

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Answered by AngelGem
0

Answer:

Explanation:

Answer:-

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