Question

k²x²-2(2k-1)x+4=0 find the value of k​

Answer 1

Answer:

k2x2 – 2 (2k – 1)x + 4 = 0 It’s of the form of ax2 + bx + c = 0 Where, a = k2, b = –2 (2k – 1), c = 4

Step-by-step explanation:

D = (-2(2k – 1))2 – 4(4)(k2) = 0 ⇒ 4k2 – 4k + 1 – 4k2 = 0 [dividing by 4 both sides] ⇒ -4k + 1 = 0 ⇒ k = 1 4 Read more on Sarthaks.com - https://www.sarthaks.com/647565/find-the-values-of-k-for-equation-have-real-and-equal-roots-k-2x-2-2-2k-1-x-4-0?show=647570#a647570