Question

k²x²-2 (k-1) x +4=0 have real and equal roots
Find the value of k

plz answer stepwise
I will surely mark u as brainliest plz​

Answer 1

Answer:

k=1/3,k= -1

Step-by-step explanation:

condition is that,

b^2-4ac=0

after simplifying the equation we get,

k^2x^2 +(2-2k)x+4=0

a=k^2,b=2-2k,c=4

(2-2k)^2-4(k^2)(4)=0

4+4k^2-8k-16k^2=0

-12k^3-8k+4=0

12k^2+8k-4=0

6k^2+4k-2=0

3k^2+2k-1=0

3k^2+3k-k-1=0

3k(k+1)-1(k+1)=0

(3k-1)(k+1)=0

k=1/3,k= -1