Question

k4p2o7 calculate oxidation number

Answer 1

k4=4(+1)

o7=7(-2)

k4p2o7=0

4(+1)+2(x)+7(-2)=0

4+2x-14=0

2x=10

x=5

Answer 2

Question :

Calculate the oxidation number of P in K₄P₂O₇ .

Answer:

+ 5

Explanation:

Let :

O.N. of P be x .

We know :

O.N. of K = + 1

O.N. of O = - 2

Here net charge on compound is zero.

= > ( 1 × 4 ) + ( x × 2 ) + ( - 2 × 7 ) = 0

= > 4 + 2 x - 14 = 0

= > 2 x - 10 = 0

= > 2 x = 10

= > x = 10 / 2

= > x = + 5 .

Therefore , O.N. of P in K₄P₂O₇ is + 5 .