Question

Ka for acetic acid is 1.75x10-5. Find Kb for acetate ion at 25oC. (Kw= 1.0 x 10-14)

Answer 1

Answer:

5.7×10^-10

Explanation:

Ka × Kb = Kw

Kb = Kw/ Ka

     = 1×10^-14/ 1.75×10^-5

Kb   = 5.7×10^-10

Answer 2

Given info : Ka for acetic acid is 1.75 × 10¯⁵.

To find : The value Kb for acetic acid at 25°C if Ionic product of water , Kw = 10¯¹⁴

solution : when acidic constant of a acid is Ka and basic constant of the given acid is Kb then,

Ka × Kb = Kw

here Kw = 10¯¹⁴ , Ka = 1.75 × 10¯⁵

∴ 10¯¹⁴ = 1.75 × 10¯⁵ × Kb

⇒Kb = (1/1.75) × 10^-9 = 5.7 × 10¯¹⁰

Therefore the Kb for acetate ion at 25° C is 5.7 × 10¯¹⁰

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