Question

Ka for CH₃COOH is 1.8 × 10⁻⁵ and Kb for NH₄OH is
1.8 × 10⁻⁵.The pH of ammonium acetate will be
(a) 7.005 (b) 4.75
(c) 7.0 (d) Between 6 and 7

Answer 1

Answer:

The answer is option c 7.0

Answer 2

The pH of ammonium acetate will be (c) 7.0.

Explanation:

Given:

$K_a$ = $1.8\times10^{-5}$

$K_b$ = $1.8\times10^{-5}$

To find:

pH of ammonium acetate = ?

Formula to be used:

pH = $\frac{1}{2}[pK_a+pK_a-pK_b]$

Calculation:

pH of ammonium acetate = $\frac{1}{2}[pK_a+pK_a-pK_b]$

pH of ammonium acetate = $\frac{1}{2}[14+log(1.8\times10^{-5})-log(1.8\times10^{-5})$

pH of ammonium acetate = $\frac{1}{2} \times14$

pH of ammonium acetate = 7

Conclusion:

From the above calculation the pH of the ammonium acetate is inferred as (c) 7.0.

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