कोई भी वस्तु सीधे ऊपर की तरफ फेंकी गई और 78.4 मीटर की ऊंचाई पर पहुंची उसका वेग ज्ञात कीजिए।(g=9.8m/s²)
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Answer:
39.2 m/s.
Explanation:
Given, s(distance)=78.4m & g=9.8m/s2.
using, v^2=u^2 + 2gs
v(final speed) to be calculated.
u(initial speed) =0.
so v^2= 2×9.8×78.4
=1536.64
v = 39.2m/s
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