Math, asked by harsh93198, 18 days ago

कोई एक सवाल हल कीजिए

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Answers

Answered by poiram576
1

Step-by-step explanation:

use some properties

every type of this question it always help you

All the best

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Answered by jitenderjakhar
0

Answer:

6.Given, cscA=2

We know,

sinA= 1/cscA = 1/2

cos A =√(1-sin²A )

cos A = √(1-1/4) = √3/2

= 1/tan A + sin A /1+cosA

= cos A /sinA + sin A /1+cos A

= 3/2 / 1/2 + 1/2 / 1+3/2

= 23 +4 /(2+3)

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