कोई एक सवाल हल कीजिए
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Step-by-step explanation:
use some properties
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6.Given, cscA=2
We know,
sinA= 1/cscA = 1/2
cos A =√(1-sin²A )
cos A = √(1-1/4) = √3/2
= 1/tan A + sin A /1+cosA
= cos A /sinA + sin A /1+cos A
= √3/2 / 1/2 + 1/2 / 1+√3/2
= 2√3 +4 /(2+√3)
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