Question

कोई व्यक्ति प्रथम माह में ₹ 50, दूसरे माह में ₹ 80, तीसरे माह में ₹ 110 तथा इसी प्रकार प्रत्येक माह बचाता है। पार
वर्ष में उसने कितनी राशि बचा ली?
A man saves ₹ 50 in first month, ₹ 80 in the second month, ₹ 110 in the third month andan
on. How much did he save in 5 years ?
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Answer 1

Answer:

960 for tha right anssssss

Answer 2

AnswEr :

• He Saves Rs.50 in First Month, Rs.80 in Second Month, Rs.110 in Third Month and so.
• Find How much he save in 5 Years.

we can see that this is in A.P. and we can find Sum of nth Term to know the saving.

◗ First Term ( a ) = Rs. 50

◗ Difference ( d ) = 80 - 50 = 110 - 80 = 30

◗ Number of Terms ( n ) = 12 Month × Years = 12 Month × 5 Years = 60

• Now we will find the Sum of 60th Term :

⇒ Sn = n /2 [ 2a + (n - 1)d ]

⇒ S₆₀ = 60 /2 [ 2 × 50 + (60 - 1) × 30 ]

⇒ S₆₀ = 30 [ 100 + 59 × 30 ]

⇒ S₆₀ = 30 [ 100 + 1770 ]

⇒ S₆₀ = 30 × 1870

⇒ S₆₀ = Rs. 56,100

∴ Man will save Rs. 56,100 in 5 Years.