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X.
Answers
Explanation:
\underline{\sf\ Solution:-}
Solution:−
Area of remaining sheet = Area of whole -(Area of 2 circles + Area of rectangle)
\begin{gathered}:\implies\sf\ Area\ of\ rectangle= Length\times breadth\\ \\ \\ :\implies\sf\ Area\ of\ circle = \pi r^2 \end{gathered}
:⟹ Area of rectangle=Length×breadth
:⟹ Area of circle=πr
2
Given :-
Radius of big circle (R) = 14cm
radius of small (r) = 3.5cm
Length of rectangle = 3cm
Breadth of rectangle= 1cm
We have to find the Area of remaining sheet
Now ,
\begin{gathered}:\implies\sf\ Remaining\ Area= \pi R^2-(2\pi r^2+\ell \times b)\\ \\ \\ :\implies\sf\ Area= \dfrac{22}{\cancel{7}}\times 14\times \cancel{14}\Big(2\times \dfrac{22}{\cancel{7}}\times \cancel{3.5}\times 3.5+ 3\times 1\Big)\\ \\ \\ :\implies\sf\ Remaining\ Area= 22\times 14\times 7\Big( 2\times 0.5\times 3.5\times22 +3\Big)\\ \\ \\ :\implies\sf\ Remaining\ Area=2156\times \Big(77+3\Big)\\ \\ \\ :\implies\sf\ Remaining\ Area= 2156\times 80\\ \\ \\ :\implies\underline{\boxed{\sf\ Remaining\ Area=172480cm^2}}\end{gathered}
:⟹ Remaining Area=πR
2
−(2πr
2
+ℓ×b)
:⟹ Area=
7
22
×14×
14
(2×
7
22
×
3.5
×3.5+3×1)
:⟹ Remaining Area=22×14×7(2×0.5×3.5×22+3)
:⟹ Remaining Area=2156×(77+3)
:⟹ Remaining Area=2156×80
:⟹
Remaining Area=172480cm
2