के का मान ज्ञात करो यदि समीकरण युग्म के असंख्य हल हो
kx+y=k
x+ky=1
Answers
Answered by
2
Given : kx+y=k
x+ky=1
समीकरण युग्म के असंख्य हल
To Find : Value of k
Solution:
a₁x + b₁y + c₁= 0 तथा
a₂x + b₂y + c₂ = 0
असंख्य हल
a₁/a₂ = b₁/ b₂ = c₁/c₂
kx+y=k
x+ky=1
k/1 = 1/k = k/1
k/1 = 1/k
=> k² = 1
=> k = ±1
k = 1
=> 1/1 = 1/1 = 1/1 = 1
k = -1
=> -1/1 = 1/-1 = 1/-1 = -1
Hence values of k = - 1
Learn More:
A pair of linear equations 111 2 2 2 ax by c ax by c + += + += 0, 0 is ...
brainly.in/question/18461075
If ax2+bx+c and bx2+ax+c have a common factor x+1 then show that ...
brainly.in/question/11220575
Similar questions
Accountancy,
1 month ago
Hindi,
1 month ago
English,
1 month ago
Math,
4 months ago
Social Sciences,
4 months ago
Science,
10 months ago
Hindi,
10 months ago