कैलकुलेट टोटल नंबर ऑफ एटम ऑफ कार्बन प्रेजेंट इन 1.6 ग्राम आफ मेथेन
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Answer:
No. of atoms of carbon present = 3.01 × 10²³ atoms
Explanation:
Molar mass of methane = 16g
1 Molecule of methane = 5 atoms
1 Mole of methane = 6.022 × 10²³
6.022 × 10²³ × 1.6 / 16 ×5
= 3.01 × 10²³
Therefore there are 3.01 × 10²³ atoms of carbon in 1.6g of
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