Chemistry, asked by pawanpreetk004, 7 months ago

कैलकुलेट टोटल नंबर ऑफ एटम ऑफ कार्बन प्रेजेंट इन 1.6 ग्राम आफ मेथेन​

Answers

Answered by Anonymous
0

Answer:

No. of atoms of carbon present = 3.01 × 10²³ atoms

Explanation:

Molar mass of methane = 16g

1 Molecule of methane = 5 atoms

1 Mole of methane = 6.022 × 10²³

6.022 × 10²³ × 1.6 / 16 ×5  

= 3.01 × 10²³

Therefore there are 3.01 × 10²³ atoms of carbon in 1.6g of CH_{4}

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