Physics, asked by MadihaFati06, 5 months ago

कैलकुलेट द एक्सेस प्रेशर इंसाइड ए ड्रॉप ऑफ वाटर ऑफ रेडियस 2 mm

Answers

Answered by Anonymous

1

Explanation:

Excessure Pressure for :

Drop of mercury =RDrop2Tsoap=2×10−32×0. 465=2×232. 5N/m2=465N/m2.

Bubble of soap =RBubble22Tsoap=4×10−32×2×0. 03=2×15N/m2=30N/m2.

Bubble of air in water =RBubble22Twater=4×10−32×2×0. 076=7×38N/m2=76N/m2.

I hope find help you..

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