Physics, asked by sanya9896, 5 months ago

कैलकुलेट द नंबर ऑफ मॉलिक्यूल ऑफ so2 प्रोड्यूस बेन 128 ग्राम्स ऑफ सल्फर इन एयर​

Answers

Answered by Anonymous
0

The molar mass of \large\rm { SO_{2}}

is 32+16+16 = 64 g/mol.

The no. of moles of \large\rm { SO_{2}} Present in 128 g of \large\rm { SO_{2}}

= \large\rm { \frac {128}{64} = 2 \ mol }

2 mole of any substance contains avogadro's number of molecules which is 12.046 × 10-²³ .

So, no. of molecules are 12.046 × 10-²³

Answered by Anonymous
1

Answer:

The molar mass of \large\rm { SO_{2}}SO

2

is 32+16+16 = 64 g/mol.

The no. of moles of \large\rm { SO_{2}}SO

2

Present in 128 g of \large\rm { SO_{2}}SO

2

= \large\rm { \frac {128}{64} = 2 \ mol }

64

128

=2 mol

2 mole of any substance contains avogadro's number of molecules which is 12.046 × 10-²³ .

So, no. of molecules are 12.046 × 10-²³

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