Math, asked by adhithyarajck, 5 months ago

कैलकुलेट द नंबर ऑफ मॉलिक्यूल प्रेजेंट इन 1 ग्राम ऑफ वॉटर​

Answers

Answered by Northkai
1

Answer:

3.3 x 10(power 22)

Step-by-step explanation:

we have molecular mass of water H2O = 1x2 + 16 = 18 gm.

And so No. of molecules in 1ml water = no. of moles x avogadro's no. = 1/18 X 6.022 x 10(power)23 =0.33 x 10(power23) molecules.

So, the no. of molecules of water in 1ml of water = 3.3 x 10(power22).

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