Question

कैलकुलेट द टोटल नंबर ऑफ एटम इन 0.5 मोल ऑफ़ K2 cr2 O7​

Answer 1

Answer:

3.3121 × 10^24 atoms

Explanation:

Atomicity —— number of total atoms present in a compound

no. of atoms = atomicity × moles × 6.022×10^23

no. of atoms = (2+2+7) × 0.5 × 6.022 × 10^23

no.of atoms = 11 × 0.5 × 6.022 × 10^23

no.of atoms = 33.121 × 10^23

no.of atoms = 3.3121 × 10^24

So there are 3.3121 × 10^24 atoms in K2Cr2O7

Answer 2

(0.5)(6.022×10 ki power 23) = 3.011 × 10 ki power 23

3.011×10 ki power 23 × 11 = 3.3121×10 ki power 24