Question

कैलकुलेट द वर्ल्ड टू बी डन टू स्टॉप अ कार ऑफ 1500 केजी मूवी एंड वेलोसिटी ऑफ​

Answer 1

QuestioN :

Calculate the work to be done to stop a car of 1500 kg moving at velocity of 60 km/h.

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Answer :

$\mathfrak{Given} \begin{cases} {\red{\sf{Mass\ of\ car\ (m)\ =\ 1500\ kg}}} \\ {\green{\sf{Velocity\ (v)\ =\ 60\ ms^{-1}}}} \\ {\blue{\sf{Work\ done\ =\ ?}}} \end{cases}$

In this case, Work Done is stored in the form of Kinetic Energy.

$\implies \sf{Work\ Done\ =\ Kinetic\ Energy} \\ \\ \\ \implies \sf{Work\ Done\ =\ \dfrac{1}{2} mv^2} \\ \\ \\ \implies \sf{Work\ Done\ =\ \dfrac{1}{2}\ \times\ 1500\ \times\ 60^2} \\ \\ \\ \implies \sf{Work\ Done\ =\ \dfrac{1500\ \times\ 3600}{2}} \\ \\ \\ \implies \sf{Work\ Done\ =\ \dfrac{5400000}{2}} \\ \\ \\ \implies \sf{Work\ Done\ =\ 2700000\ J} \\ \\ \\ \implies \sf{Work\ Done\ =\ \dfrac{2700000}{1000}\ kJ} \\ \\ \\ \implies {\boxed{\sf{Work\ Done\ =\ 2700\ kJ}}}$

$\underline{\sf{\therefore \: Work\ done\ to\ stop\ car\ is\ 2700\ kJ}}$

Answer 2

Answer:

Given:

• Mass (m) = 1500 kg.
• Velocity (v) = 60 km/hr

Find:

• Calculate the work done.

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{Work \: done = \dfrac{1}{2} (mv)^{2} }}}}}}$

Calculations:

⇒ $\bold{Work \: done = 750 \times 60^{2}}$

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⇒ $\bold{Work \: done = 750 \times 60 \times 60}$

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⇒ $\bold{Work \: done = 750 \times 3600}$

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⇒ $\bold{Work \: done = 2700000 \: J}$

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⇒ $\bold{Work \: done = \cancel{\dfrac{2700000}{1000}}}$

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⇒ ${\sf{\underline{\boxed{\red{\sf{2700 \: KJ}}}}}}$

Therefore, 2700 KJ is work done.