Hindi, asked by Anonymous, 9 months ago

कोमलता के बाद से..
प्रदान करने मे ही अपने कर्तत्य की इच्छा मानता है।
If u know the answer than u answer me...
please please

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Answers

Answered by jitubannarj19
0

Apne Kartavya ki Palna Karen arthat Pushp ki Abhilasha Hai Ki vah Veer Sainik ke Pairon Mein Kushal kar Apne Bhagya ko Dhanya kar le

Answered by Anonymous
0

Explanation:

.:

 \bf  \blue{\large  \bf\underline{  \bf\underline{Question}}}

X^2+6x+7.................

____________________________

 \bf  \blue{\large  \bf\underline{  \bf\underline{solution}}}

\bf \green{\underline{according \: to \: the \: quadratic \: formula}}

The quadratic formula is a formula that provides the solution to a quadratic equation.

________________________________

\bf \blue {\underline {The  \: Quadratic \:  Formula \to}}

\bf  \pink{For \: v \:  =  {ax}^{2}  + bx + c}

The values of x which are the solutions of the equation are given by:

 \bf  \: x \:  =  \frac{-b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\\\

\bf \blue {\underline {According\to}}

\sf \: {ax}^{2}  + bx \:  + c

________________________________

Then,

\bf \red{a = 1}

\bf \blue{b=  + 6}

\bf \green{c=  7}

\bf \blue{putting \: all \: values}\\

\sf  \: x \:  =  \frac{-(+6) \pm \sqrt{ {+6}^{2} - 4 \times 1 \times 7} }{2 \times 1}  \\  \\

\sf  \: x \:  =  \frac{-6 \pm \sqrt{ 36 - 28} }{2 }  \\  \\

 \sf  \: x \:  = \frac{-6 \pm \sqrt{ 8} }{2 } \\

\bf \blue{  On  \: doing  \: +}

 \sf  \: x \:  = \frac{-6 + \sqrt{ 8} }{2 } \\\\

\sf  \green{x \:  = - 3 + \sqrt{ 8} }\\\\

\bf \blue{  On  \: doing  \: -}

\sf  \: x \:  = \frac{ - 6 - \sqrt{ 8} }{2 } \\\\

\sf  \green{x \:  = - 3 - \sqrt{ 8} }\\\\

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