Ka of acetic acid is 1.8 X 10⁻⁵ if [salt] =[acid] = 0.1 M . pH of the solution containing acetic acid and sodium acetate would be about *
A.7
B. 4.7
C. 5.3
D. 1.4
Answers
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4
Answer:
dissociation of acetic acid can be represented as:
CH
3
COOH↔H
+
+CH
3
COO
−
HCl dissociated completely.
Now, let the concentration of acetate ion be x.
Therfore, hydrogen ion contribution from acetic acid=x
Since HCL dissociated completely, hydrogen ion contribution from HCl=0.1 M
Total [H
+
] concetration=x+0.1
Now, K
a
for acetic acid=1.8×10
−5
Hence,
K
a
=
CH
3
COOH]
[CH
3
COO
−
][H
+
]
1.8×10
−5
=
0.2
x(x+0.1)
0.36×10
−5
=x(x+0.1)
x
2
+0.1x−0.36×10
−5
x=0.35×10
−4
Percentage dissociation=
0.2
0.35×10
−4
×100
=0.0175≈0.018
Explanation:
hope it's help you
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