Question

Ka of Sulfurous acid is 1.54 x 10^-2, what is the Kb value of it's conjugate base ​

Answer 1

Answer:

1.54 x 10upward

Explanation:

$x^{2} \sqrt{x} \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \pi \frac{x}{y}$