Question

कार्डबोर्ड बॉक्स इज 50 सेंटीमीटर लॉन्ग 40 सेंटीमीटर एंड 4 सेंटीमीटर फाइंड द वॉल्यूम ऑफ द बॉक्स​

Answer 1

Step-by-step explanation:

Total surface area of cuboid = 2(lb + bh + lh) Given: l = 40 cm , b = 50 cm , h = 60 cm Therefore, Total surface area of cuboid = 2 [( 40 x 50 ) + ( 50 )

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Answer 2

Answer:

Total surface area of cuboid = 2(lb+bh+lh)

Given:

l=40cm, b=50cm, h = 60cm

Therefore,

Total surface area of cuboid = 2[(40 x 50) +(50 x 60) + (60 x 40)]

• = 2[2000+3000+2400] = 2(7400)

Hence the total surface area of cuboid = area of the foil needed for covering it = 14,800 cm²