कारखाने की मशीनों की मरम्मत के लिए कुछ सामान की आवश्यकता है विक्रेता को पत्र लिखिए
Answers
Explanation:
《¤¤¤¤¤¤¤¤¤¤¤¤¤¤》
☆ Given :
Polynomial = 12x²-4x+3x-1 i.e.12x² -x -1
___________________________
☆ To Calculate :
Zeros of the polynomial 12x²-4x+3x-1.
___________________________
☆ Also To Verify :
Relationship between Zeros And Coefficient.
___________________________
¤ Relationship between
Zeros And Coefficients :
If a Polynomial is of the Form ax² + bx + c.
and it's zeros are α and β.
Then,
α + β = -b/a
and
αβ = c/a
___________________________
☆ Solution :
《♤ {Calculating Zeros}♤》
12x²-4x+3x-1
= 4x(3x - 1) + 1(3x - 1 )
= (3x - 1)(4x+1)
So,
Zeros of the given polynomial are 1/3 and -1/4.
●》α= 1/3 and β = -1/4
《♤{Verifying Releationship}♤》
\begin{gathered} \sf\alpha + \beta = \frac{1}{3} + ( \frac{ - 1}{4} ) \\ \\ = \frac{1}{3} - \frac{1}{4} \\ \\ = \frac{1}{12} = \bf- \frac{b}{a} \: \: \: \{verified \}\end{gathered}
α+β=
3
1
+(
4
−1
)
=
3
1
−
4
1
=
12
1
=−
a
b
{verified}
\begin{gathered} \sf\alpha \beta = \frac{1}{3} \times ( - \frac{1}{4} ) \\ \\ = - \frac{1}{12} = \bf \frac{c}{a} \: \: \: \: \{verified \}\end{gathered}
αβ=
3
1
×(−
4
1
)
=−
12
1
=
a
c
{verified}
___________________________I am a sk sabir boss
Given :-
Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years.
To Find :-
Age of each
Solution :-
Let the age of Baichung be B
Age of father = B + 26
Age of grandfather = B + 26 + 29
Age of grandfather = B + 55
Now
(B) + (B + 26) + (B + 55) = 135
3B + 81 = 135
3B = 135 - 81
3B = 54
B = 54/3
B = 18
Now
Age of Baichung = 18 years
Age of his father = 18 + 26 = 44 years
Age of grandfather = 18 + 55 = 73 years