Question

किसी A.P. का 7वाँ पद 20 और 13वाँ पद 32 है। A.P. ज्ञात कीजिए।

Answer 1

a7=20

a+6d=20→1st eq^n

a13=32

a+12d=32→2nd eq^n

Subtracting 1st and 2nd eq^ns

a+6d-a-12d=20-32

-6d=-12

d=-12/-6

d=2

put d=2 in 1st eq^n

a+6(2)=20

a+12=20

a=8

So, AP is 8,14,20,26,32,38…

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Answer 2

Answer:

7वाॅ पद=20

a+(7-1)d=20

a+6d=20............(1)

13वाॅ पद=32

a+(13-1)d=32

a+12d=32 ...........(2)

On solving (1)&(2) ,we obtain

a=8 ,d=2

Hence A.p series a,a+d,a+2d,a+3d,.........to n term

8,10,12,14,16,........nterm