किसी परीक्षा में उत्तीर्ण होने के लिए एक परीक्षार्थी को पूर्णांक के 33% अंक प्राप्त करने हैं, उसे 225 अंक मिले हैं जो कि 33% से 6 का अंक का थे। बताइए परीक्षा में पूर्णांक क्या था?
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Answered by
3
Step-by-step explanation:
Step-by-step explanation:
Let the Maximum Mark (MM) of exam was x.
Since, the examini scored 225 marks which was 6 marks less than passing mark.
Therefore,
Passing mark = 225 + 6 = 231
Passing percentage = 33%
\begin{gathered}\therefore 33 \% \: of \: x \: = 231 \\\therefore \frac{33}{100} \times x = 231 \\ \therefore x = \frac{231 \times 100}{33} \\ \therefore x = 7 \times 100 \\ \therefore x = 700 \\ hence \: the \: maximum \: mark \\ \: (mm) \: of \: the \: exam \: was \: 700\end{gathered}
∴33%ofx=231
∴
100
33
×x=231
∴x=
33
231×100
∴x=7×100
∴x=700
hencethemaximummark
(mm)oftheexamwas700
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