. किसी समान्तर श्रेणी का nवा पद Tn=
{n([n×n]+5)}/4
हो तो श्रेणी ज्ञात करो।
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Answer:
sorry but I don't know Hindi but I will try to do it j don't know whether I am right or wrong
Step-by-step explanation:
(n(n+n)+5)4
n(2n)+5×4
n(2n)20
n×2n=20
3n=20
n=20/3
n=6.66
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