Question

किसी त्रिभुज के कोण (x-40) , (x-20 ) तथा (x-10) है । x का मान ज्ञात किजिए।​

Answer 1

Step-by-step explanation:

as, we know sum of all interior angle of triangle is 180°

so,

(x-40)+(x-20)+(x-10)=180°

=x-40+x-20+x-10=180°

=3x=180°+70°

=3x=250°

=x=250°/3

=x=63.3333333........

HOPE IT WILL HELP YOU!!!