Physics, asked by akiraaakhya6126, 11 months ago

किसी ट्रांजिस्टर के उभयनिष्ठ आधार परिपथ में धारा प्रवर्धन गुणांक 0.95 है। जब उत्सर्जक धारा 2 mA है तब आधार धार है।
(अ) 0.1 mA
(ब) 0.2 mA
(स) 0.19 mA
(द) 1.9 mA

Answers

Answered by aristeus
1

Base current will be 0.1 mA

So option (A) will be correct answer

Explanation:

It is given that transistor is common base \alpha =0.95

Emitter current I_A=2mA

We know that for common base configuration \alpha =\frac{I_C}{I_E}

So 0.95 =\frac{I_C}{2}

I_C=1.9mA

For common base configuration we know that

I_E=I_C+I_B

So I_B=I_E-I_C=2-1.9=0.1mA

So base current current in the common emitter configuration will be 0.1 mA

So option (A) will be correct option

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